1852 United States presidential election in Delaware

The 1852 United States presidential election in Delaware took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.


November 2, 1852
 
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William A. Graham
Electoral vote 3 0
Popular vote 6,318 6,293
Percentage 49.85% 49.66%

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

Delaware voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Delaware by a margin of 0.19%.

Results

United States presidential election in Delaware, 1852[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 6,318 49.85% 3 100.00%
Whig Winfield Scott of New Jersey William Alexander Graham of North Carolina 6,293 49.66% 0 0.00%
Free Soil John P. Hale of New Hampshire George Washington Julian of Indiana 62 0.49% 0 0.00%
Total 12,673 100.00% 3 100.00%
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References

  1. "1852 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 17 March 2015.


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