1832 United States presidential election in Delaware

The 1832 United States presidential election in Delaware took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1832 United States presidential election
United States presidential election in Delaware, 1832
November 2 – December 5, 1832
 
Nominee Henry Clay Andrew Jackson
Party National Republican Democratic
Home state Kentucky Tennessee
Running mate John Sergeant Martin Van Buren
Electoral vote 3 0
Popular vote 4,276 4,110
Percentage 50.99% 49.01%
Elections in Delaware

Delaware voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Delaware by a margin of 0.98%.

Results
United States presidential election in Delaware, 1832[1]
Party Candidate Votes Percentage Electoral votes
National Republican Henry Clay 4,276 50.99% 3
Democratic Andrew Jackson 4,110 49.01% 0
Totals 8,386 100.00% 3
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References
  1. "1832 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 12 April 2013.


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