1828 United States presidential election in Delaware

The 1828 United States presidential election in Delaware took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1828 United States presidential election
United States presidential election in Delaware, 1828
October 31 – December 2, 1828
 
Nominee John Quincy Adams Andrew Jackson
Party National Republican Democratic
Home state Massachusetts Tennessee
Running mate Richard Rush John C. Calhoun
Electoral vote 3 0
Elections in Delaware

Delaware cast 3 electoral votes for the National Republican candidate, John Quincy Adams, over the Democratic candidate, Andrew Jackson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote.[1]

Results
United States presidential election in Delaware, 1828[2]
Party Candidate Votes Percentage Electoral votes
National Republican John Quincy Adams – – 3
Democratic Andrew Jackson – – 0
Totals – – 3
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References
  1. "1828 Presidential General Election Results". U.S. Election Atlas. Retrieved 13 April 2013.
  2. "Electoral Votes for President and Vice President 1821-1837". National Archives and Records Administration. Retrieved 2 March 2013.


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