1852 United States presidential election in Wisconsin

The 1852 United States presidential election in Wisconsin was held on November 2, 1852 as part of the 1852 United States presidential election. State voters chose five electors to the Electoral College, who voted for President and Vice President.

Main article: 1852 United States presidential election

1852 United States presidential election in Wisconsin

November 2, 1852

Nominee Franklin Pierce Winfield Scott John P. Hale Party Democratic Whig Free Soil Home state New Hampshire New Jersey New Hampshire Running mate William R. King William A. Graham George W. Julian Electoral vote 5 0 0 Popular vote 33,658 22,210 8,814 Percentage 52.04% 34.34% 13.63%

County Results Pierce   30-40%   40-50%   50-60%   60-70%   80-90% Scott   40-50%   50-60% Hale   30-40%   40-50%

President before election Millard Fillmore Whig Elected President Franklin Pierce Democratic

Democratic Party candidate Franklin Pierce won the state with 52% of the popular vote, winning Wisconsin's five electoral votes.[1]

This would be the final time a Democratic presidential candidate would win Wisconsin until Grover Cleveland won the state in 1892 and one to win the state with a majority of the popular vote until Franklin D. Roosevelt won it in 1932.

Results

1852 United States presidential election in Wisconsin
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Democratic	Franklin Pierce of New Hampshire	William Rufus DeVane King of Alabama	33,658	52.04%	5	100.00%
	Whig	Winfield Scott of New Jersey	William Alexander Graham of North Carolina	22,210	34.34%	0	0.00%
	Free Soil	John Parker Hale of New Hampshire	George Washington Julian of Indiana	8,814	13.63%	0	0.00%
Total				64,682	100.00%	5	100.00%

References

1. "1852 Presidential General Election Results - Wisconsin". Retrieved August 17, 2016.