1900 United States presidential election in Delaware
The 1900 United States presidential election in Delaware took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Delaware voters chose 3 electors to the Electoral College, which selected the president and vice president.
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Elections in Delaware | ||||||||||||
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Delaware was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.
Results
United States presidential election in Delaware, 1900[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | William McKinley | 22,535 | 53.67% | 3 | |
Democratic | William Jennings Bryan | 18,852 | 44.90% | 0 | |
Prohibition | John Woolley | 546 | 1.30% | 0 | |
Social Democratic | Eugene Debs | 56 | 0.13% | 0 | |
Totals | 41,989 | 100.00% | 3 | ||
Voter turnout | — |
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References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
Notes
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