1892 United States presidential election in Delaware
The 1892 United States presidential election in Delaware took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Delaware voters chose 3 electors to the Electoral College, which selected the president and vice president.
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Delaware was won by the Democratic nominees, former President Grover Cleveland of New York and his running mate Adlai Stevenson I of Illinois.
Results
United States presidential election in Delaware, 1892[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Grover Cleveland | 18,581 | 49.90% | 3 | |
Republican | Benjamin Harrison (incumbent) | 18,077 | 48.55% | 0 | |
Prohibition | John Bidwell | 564 | 1.51% | 0 | |
Write-ins | Scattered | 13 | 0.03% | 0 | |
Totals | 37,235 | 100.00% | 3 | ||
Voter turnout | — |
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gollark: I am not sure.
gollark: It's roughly an ender dragon, and I can but I don't know how permanent it is.
gollark: Well, ender dragons can pass through things.
gollark: I'm not sure if we could box it in [HG]Tech™, but we could certainly move it.
References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
Notes
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