1792 United States presidential election in Delaware

The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792 as part of the 1792 United States presidential election. The state legislature chose 3 members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

1792 United States presidential election in Delaware

November 2 – December 5, 1792
 
Nominee George Washington John Adams
Party Nonpartisan Federalist
Home state Virginia Massachusetts
Electoral vote 3 3
Percentage 100%

President before election

George Washington
Nonpartisanism

Elected President

George Washington
Nonpartisanism

Delaware's 3 electors each cast 1 vote for the incumbent, George Washington, and 1 vote for John Adams, the incumbent Vice President.[1]

Results

United States presidential election in Delaware, 1792
Party Candidate Votes Percentage Electoral votes
Nonpartisan George Washington 100.00% 3
Totals 100.00% 3
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References

  1. Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.
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