1792 United States presidential election in Delaware
The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792 as part of the 1792 United States presidential election. The state legislature chose 3 members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.
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Elections in Delaware | ||||||||||||
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Delaware's 3 electors each cast 1 vote for the incumbent, George Washington, and 1 vote for John Adams, the incumbent Vice President.[1]
Results
United States presidential election in Delaware, 1792 | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Nonpartisan | George Washington | 100.00% | 3 | ||
Totals | 100.00% | 3 | |||
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References
- Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.
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