1792 United States presidential election in Delaware

The 1792 United States presidential election in Delaware took place between November 2 and December 5, 1792 as part of the 1792 United States presidential election. The state legislature chose 3 members of the Electoral College, each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.

Main article: 1792 United States presidential election
1792 United States presidential election in Delaware
November 2 – December 5, 1792
 
Nominee George Washington John Adams
Party Nonpartisan Federalist
Home state Virginia Massachusetts
Electoral vote 3 3
Percentage 100% –
President before election

George Washington
Nonpartisanism

 Elected President

George Washington
Nonpartisanism

Elections in Delaware

Delaware's 3 electors each cast 1 vote for the incumbent, George Washington, and 1 vote for John Adams, the incumbent Vice President.[1]

Results
United States presidential election in Delaware, 1792
Party Candidate Votes Percentage Electoral votes
Nonpartisan George Washington 100.00% 3
Totals 100.00% 3
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References
  1. Presidential Electoral Vote Count Dave Leip's Atlas of U.S. Presidential Elections.
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