1852 United States presidential election in Michigan
The 1852 United States presidential election in Michigan took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.
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Results by county
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Elections in Michigan | ||||||||||
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Michigan voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott and Free Soil candidate John P. Hale. Pierce won Michigan by a margin of 9.62%.
As of the 2016 presidential election, this is the last and only time Sanilac County voted for a Democratic Presidential candidate.[1] It would be the last time Michigan would send a full slate of Democratic electors to the Electoral College until Franklin Delano Roosevelt in 1932, although it did send five Grover Cleveland electors in 1892.[2]
Results
Party | Candidate | Votes | % | |
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Democratic | Franklin Pierce | 41,842 | 50.45% | |
Whig | Winfield Scott | 33,860 | 40.83% | |
Free Soil | John P. Hale | 7,237 | 8.73% | |
Total votes | 82,939 | 100% |
References
- Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 222-227 ISBN 0786422173
- Menendez; The Geography of Presidential Elections in the United States, p. 62
- "1852 Presidential General Election Results -Michigan". U.S. Election Atlas. Retrieved 2 December 2017.
- "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.