1868 United States presidential election in Delaware
The 1868 United States presidential election in Delaware took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for president and vice president.
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Elections in Delaware | ||||||||||||
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Delaware voted for the Democratic nominee, Horatio Seymour, over the Republican nominee, Ulysses S. Grant. Seymour won the state by a margin of 18%.
With 59% of the popular vote, Delaware would prove to be Seymour's fifth strongest state in terms of popular vote percentage after Kentucky, Louisiana, Maryland and Georgia.[1]
Results
United States presidential election in Delaware, 1868[2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Horatio Seymour of New York | Francis Preston Blair, Jr. of Missouri | 10,957 | 59.00% | 3 | 100.00% | ||
Republican | Ulysses S. Grant of Illinois | Schuyler Colfax of Indiana | 7,614 | 41.00% | 0 | 0.00% | ||
Total | 18,571 | 100.00% | 3 | 100.00% |
gollark: `index`
gollark: <@160279332454006795> Can't, dealing with a MONASTIC YARDMASTERS scenario.
gollark: Hmm, guess that function is highly antimemetic now, should have expected as much.
gollark: ++magic py reveal_antimemes()
gollark: Like what?
References
- "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1868 Presidential General Election Results - Delaware".
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