1904 United States presidential election in Delaware
The 1904 United States presidential election in Delaware took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. Delaware voters chose 3 electors to the Electoral College, which selected the president and vice president.
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| Elections in Delaware | ||||||||||||
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Delaware was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana.
Results
| United States presidential election in Delaware, 1904[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | Theodore Roosevelt | 23,705 | 54.05% | 3 | |
| Democratic | Alton B. Parker | 19,347 | 44.11% | 0 | |
| Prohibition | Silas C. Swallow | 607 | 1.38% | 0 | |
| Social Democratic | Eugene Debs | 146 | 0.33% | 0 | |
| Populist | Thomas E. Watson | 51 | 0.12% | 0 | |
| Totals | 43,856 | 100.00% | 3 | ||
| Voter turnout | — | ||||
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References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Delaware
Notes
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