1852 United States presidential election in Vermont
The 1852 United States presidential election in Vermont took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
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Vermont voted for the Whig Party candidate, Winfield Scott, over the Democratic candidate, Franklin Pierce. Scott won the state by a margin of 20.8%. This would be the last election until 1916 where a Democratic candidate won more than 40% of the vote in a Vermont county.
Vermont was one of the only four states to vote for Scott. The other three were Massachusetts, Kentucky, and Tennessee.
With 50.52% of the popular vote, Vermont would prove to be Scott's third strongest state after Kentucky and Tennessee.[1]
Free Soil Party candidate John P. Hale won 19.64% of the popular vote in the state, making Vermont his second strongest state after neighboring Massachusetts. Lamoille County was won by Hale, which would make him the final third party candidate to win a single county in Vermont until Progressive Party candidate Theodore Roosevelt won six counties in 1912. This election would also mark the last time Vermont did not vote for the Republican candidate until 1964, more than a century later.
Results
1852 United States presidential election in Vermont[2] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Whig | Winfield Scott | 22,173 | 50.52% | 5 | |
Democratic | Franklin Pierce | 13,044 | 29.72% | 0 | |
Free Soil | John P. Hale | 8,621 | 19.64% | 0 | |
None | Write-ins | 52 | 0.12% | 0 | |
Totals | 43,890 | 100% | 5 |
References
- "1852 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1852 Presidential General Election Results - Vermont". U.S. Election Atlas. David Leip. Retrieved 2017-03-17.