1852 United States presidential election in Louisiana

The 1852 United States presidential election in Louisiana took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.

1852 United States presidential election in Louisiana

November 2, 1852
 
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William A. Graham
Electoral vote 6 0
Popular vote 18,647 17,225
Percentage 51.94% 48.06%

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

Louisiana voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Louisiana by a margin of 3.88%.

Results

United States presidential election in Louisiana, 1852[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 18,647 51.94% 6 100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 17,225 48.06% 0 0.00%
Total 35,872 100.00% 6 100.00%
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References

  1. "1852 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved 2 December 2017.
  2. "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.


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