1852 United States presidential election in Louisiana
The 1852 United States presidential election in Louisiana took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Louisiana |
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Presidential Elections
U.S. Senate
U.S. House
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State elections by year
Gubernatorial
Lieutenant gubernatorial Attorney General |
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Louisiana voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Louisiana by a margin of 3.88%.
Results
United States presidential election in Louisiana, 1852[1][2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 18,647 | 51.94% | 6 | 100.00% | ||
Whig | Winfield Scott of New Jersey | William A. Graham of North Carolina | 17,225 | 48.06% | 0 | 0.00% | ||
Total | 35,872 | 100.00% | 6 | 100.00% |
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References
- "1852 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved 2 December 2017.
- "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.
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