1840 United States presidential election in Delaware

The 1840 United States presidential election in Delaware took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1840 United States presidential election
United States presidential election in Delaware, 1840
October 30 - December 2, 1840
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate John Tyler none
Electoral vote 3 0
Popular vote 5,967 4,872
Percentage 54.99% 44.89%
President before election

Martin Van Buren
Democratic

 Elected President

William Henry Harrison
Whig

Elections in Delaware

Delaware voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Delaware by a margin of 10.1%.

Results
United States presidential election in Delaware, 1840[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig William Henry Harrison of Ohio John Tyler of Virginia 5,967 54.99% 3 100.00%
Democratic Martin Van Buren of New York Richard M. Johnson of Kentucky 4,872 44.89% 0 0.00%
N/A Others Others 13 0.12% 0 0.00%
Total 10,852 100.00% 3 100.00%
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References
  1. "1840 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 23 December 2013.


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