1844 United States presidential election in Delaware
The 1844 United States presidential election in Delaware took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Delaware | ||||||||||||
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Delaware voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won Delaware by a margin of 2.45%.
Results
United States presidential election in Delaware, 1844[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 6,271 | 51.20% | 3 | 100.00% | ||
Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 5,970 | 48.75% | 0 | 0.00% | ||
N/A | Others | Others | 6 | 0.05% | 0 | 0.00% | ||
Total | 12,247 | 100.00% | 3 | 100.00% |
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References
- "1844 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved 23 December 2013.
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