1852 United States presidential election in Arkansas

The 1852 United States presidential election in Arkansas took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1852 United States presidential election
United States presidential election in Arkansas, 1852
November 2, 1852
 
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William A. Graham
Electoral vote 4 0
Popular vote 12,173 7,404
Percentage 62.18% 37.82%
President before election

Millard Fillmore
Whig

 Elected President

Franklin Pierce
Democratic

Elections in Arkansas

Arkansas voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Arkansas by a margin of 24.36%.

Results
United States presidential election in Arkansas, 1852[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 12,173 62.18% 4 100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 7,404 37.82% 0 0.00%
Total 19,577 100.00% 4 100.00%
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References
  1. "1852 Presidential General Election Results - Arkansas". U.S. Election Atlas. Retrieved 1 December 2017.
  2. "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 1 December 2017.


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