1852 United States presidential election in Maryland
The 1852 United States presidential election in Maryland took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose 8 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Maryland | ||||||||
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Elections by year |
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Maryland voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Maryland by a margin of 6.59%. This was the first presidential election in which Maryland voted Democratic.
Results
United States presidential election in Maryland, 1852[1][2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Pierce of New Hampshire | William R. King of Alabama | 40,022 | 53.28% | 8 | 100.00% | ||
Whig | Winfield Scott of New Jersey | William A. Graham of North Carolina | 35,077 | 46.69% | 0 | 0.00% | ||
Free Soil | John P. Hale of New Hampshire | George W. Julian of Indiana | 21 | 0.03% | 0 | 0.00% | ||
Total | 75,120 | 100.00% | 8 | 100.00% |
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References
- "1852 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 2 December 2017.
- "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.
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