2018 Florida House of Representatives election

The 2018 Florida House of Representatives election was held in the U.S. state of Florida on November 6, 2018, to elect members to the House of Representatives. The election coincided with the election for governor, and other elections. The Republicans won 73 seats and losing only 2, maintaining their control since 1997, while the Democrats gained 6 seats.[1] Four vacant seats, all won by Republicans in 2016, were picked up by Democrats.

2018 Florida House of Representatives election
November 6, 2018 (2018-11-06)
All 120 seats in the Florida House of Representatives
61 seats needed for a majority
  Majority party Minority party
 
Leader Richard Corcoran Janet Cruz
Party Republican Democratic
Leader since November 22, 2016 November 21, 2016
Leader's seat 37th–Dade City 62nd–Tampa
Last election 79 seats, 57.08% 41 seats, 39.77%
Seats before 75 41
Seats won 73 47
Seat change 2 6
Popular vote 3,320,015 2,494,934
Percentage 56.21% 42.24%
Results by district
Speaker before election

Richard Corcoran
Republican

 Elected Speaker

José R. Oliva
Republican

Elections in Florida
Government

Results
Party Votes Seats
No. % No. +/− %
Republican Party of Florida 3,320,015 56.21 73 −2 60.83
Florida Democratic Party 2,494,934 42.24 47 +6 39.16
Independent 81,720 1.38 0 0 0.00
Libertarian Party of Florida 5,381 0.32 0 0 0.00
Green Party of Florida 4,622 0.32 0 0 0.00
Write-in 3,925 0.15 0 0 0.00
Total 5,906,926 100.00 134 ±0 100.00
Source: Florida Division of Elections[2]
Popular vote
Republican
 
 56.21%
Democratic
 
 42.24%
Other
 
 0.83%
House seats
Republican
 
 60.83%
Democratic
 
 39.16%
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References
  1. https://ballotpedia.org/Florida_House_of_Representatives_elections,_2018
  2. https://results.elections.myflorida.com/Index.asp?ElectionDate=11/6/2018&DATAMODE=
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