2018 Florida House of Representatives election

The 2018 Florida House of Representatives election was held in the U.S. state of Florida on November 6, 2018, to elect members to the House of Representatives. The election coincided with the election for governor, and other elections. The Republicans won 73 seats and losing only 2, maintaining their control since 1997, while the Democrats gained 6 seats.[1] Four vacant seats, all won by Republicans in 2016, were picked up by Democrats.

2018 Florida House of Representatives election

November 6, 2018 (2018-11-06)
All 120 seats in the Florida House of Representatives 61 seats needed for a majority
Majority party Minority party   Leader Richard Corcoran Janet Cruz Party Republican Democratic Leader since November 22, 2016 November 21, 2016 Leader's seat 37th–Dade City 62nd–Tampa Last election 79 seats, 57.08% 41 seats, 39.77% Seats before 75 41 Seats won 73 47 Seat change 2 6 Popular vote 3,320,015 2,494,934 Percentage 56.21% 42.24%
Results by district
Speaker before election Richard Corcoran Republican Elected Speaker José R. Oliva Republican

Results

Party		Votes		Seats
		No.	%	No.	+/−	%
	Republican Party of Florida	3,320,015	56.21	73	−2	60.83
	Florida Democratic Party	2,494,934	42.24	47	+6	39.16
	Independent	81,720	1.38	0	0	0.00
	Libertarian Party of Florida	5,381	0.32	0	0	0.00
	Green Party of Florida	4,622	0.32	0	0	0.00
	Write-in	3,925	0.15	0	0	0.00
Total		5,906,926	100.00	134	±0	100.00
Source: Florida Division of Elections[2]

Popular vote Republican   56.21% Democratic   42.24% Other   0.83%

House seats Republican   60.83% Democratic   39.16%

References

1. https://ballotpedia.org/Florida_House_of_Representatives_elections,_2018
2. https://results.elections.myflorida.com/Index.asp?ElectionDate=11/6/2018&DATAMODE=