1928 United States presidential election in Iowa
The 1928 United States presidential election in Iowa took place on November 6, 1928. All contemporary 48 states were part of the 1928 United States presidential election. Voters chose thirteen electors to the Electoral College, which selected the president and vice president.
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Iowa was won by Republican Secretary of Commerce Herbert Hoover of California, who was running against Democratic list of Governors of New York Alfred E. Smith. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith's running mate was Senator Joseph Taylor Robinson of Arkansas. Hoover won Iowa by a margin of 24.20%.
Results
Presidential Candidate | Running Mate | Party | Electoral Vote (EV) | Popular Vote (PV) | |
---|---|---|---|---|---|
Herbert Hoover of California | Charles Curtis | Republican | 13[1] | 623,570 | 61.77% |
Al Smith | Joseph T. Robinson | Democratic | 0 | 379,311 | 37.57% |
Frank Webb | Will Vereen | Farmer-Labor | 0 | 3,088 | 0.31% |
Norman Thomas | James Maurer | Socialist | 0 | 2,960 | 0.29% |
William Z. Foster | Benjamin Gitlow | Communist | 0 | 328 | 0.03% |
Verne L. Reynolds | Jeremiah Crowley | Socialist Labor | 0 | 230 | 0.02% |
— | — | Write-ins | 0 | 2 | 0.00% |
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References
- "1928 Presidential General Election Results – Iowa". Dave Leip’s U.S. Election Atlas. Retrieved 28 December 2019.
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