1928 United States presidential election in Iowa

The 1928 United States presidential election in Iowa took place on November 6, 1928. All contemporary 48 states were part of the 1928 United States presidential election. Voters chose thirteen electors to the Electoral College, which selected the president and vice president.

Main article: 1928 United States presidential election

1928 United States presidential election in Iowa

November 6, 1928

Nominee Herbert Hoover Al Smith Party Republican Democratic Home state California New York Running mate Charles Curtis Joseph T. Robinson Electoral vote 13 0 Popular vote 623,570 379,311 Percentage 61.77% 37.57%

County Results Hoover   50-60%   60-70%   70-80% Smith   50-60%   60-70%

President before election Calvin Coolidge Republican Elected President Herbert Hoover Republican

Iowa was won by Republican Secretary of Commerce Herbert Hoover of California, who was running against Democratic list of Governors of New York Alfred E. Smith. Hoover's running mate was Senate Majority Leader Charles Curtis of Kansas, while Smith's running mate was Senator Joseph Taylor Robinson of Arkansas. Hoover won Iowa by a margin of 24.20%.

Results

Presidential Candidate	Running Mate	Party	Electoral Vote (EV)	Popular Vote (PV)
Herbert Hoover of California	Charles Curtis	Republican	13[1]	623,570	61.77%
Al Smith	Joseph T. Robinson	Democratic	0	379,311	37.57%
Frank Webb	Will Vereen	Farmer-Labor	0	3,088	0.31%
Norman Thomas	James Maurer	Socialist	0	2,960	0.29%
William Z. Foster	Benjamin Gitlow	Communist	0	328	0.03%
Verne L. Reynolds	Jeremiah Crowley	Socialist Labor	0	230	0.02%
—	—	Write-ins	0	2	0.00%

References

1. "1928 Presidential General Election Results – Iowa". Dave Leip’s U.S. Election Atlas. Retrieved 28 December 2019.