1944 United States presidential election in Iowa

The 1944 United States presidential election in Iowa took place on November 7, 1944, as part of the 1944 United States presidential election. Iowa voters chose ten[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Main article: 1944 United States presidential election
1944 United States presidential election in Iowa
November 7, 1944[1]
All 10 Iowa votes to the Electoral College
 
Nominee Thomas E. Dewey Franklin D. Roosevelt
Party Republican Democratic
Home state New York New York
Running mate John W. Bricker Harry S. Truman
Electoral vote 10 0
Popular vote 547,267 499,876
Percentage 51.9% 47.5%
County Results
President before election

Franklin D. Roosevelt
Democratic

 Elected President

Franklin D. Roosevelt
Democratic

Elections in Iowa

Iowa was won by Governor Thomas E. Dewey (R–New York), running with Governor John Bricker, with 51.99% of the popular vote, against incumbent President Franklin D. Roosevelt (D–New York), running with Senator Harry S. Truman, with 47.49% of the popular vote.[3][4]

Results
1944 United States presidential election in Iowa
Party Candidate Votes %
Republican Thomas E. Dewey 547,267 51.99%
Democratic Franklin D. Roosevelt (inc.) 499,876 47.49%
Prohibition Claude A. Watson 3,752 0.36%
Write-in 1,704 0.16%
Total votes 1,052,599 100%
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References
  1. "United States Presidential election of 1944 - Encyclopædia Britannica". Retrieved December 22, 2017.
  2. "1944 Election for the Fortieth Term (1945-49)". Retrieved December 22, 2017.
  3. "1944 Presidential General Election Results - Iowa". Retrieved December 22, 2017.
  4. "The American Presidency Project - Election of 1944". Retrieved December 22, 2017.


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