1964 United States presidential election in Iowa

The 1964 United States presidential election in Iowa took place on November 3, 1964, as part of the 1964 United States presidential election. Iowa voters chose nine[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

Main article: 1964 United States presidential election
1964 United States presidential election in Iowa
November 3, 1964[1]
 
Nominee Lyndon B. Johnson Barry Goldwater
Party Democratic Republican
Home state Texas Arizona
Running mate Hubert Humphrey William E. Miller
Electoral vote 9 0
Popular vote 733,030 449,148
Percentage 61.9% 37.9%
County Results
President before election

Lyndon B. Johnson
Democratic

 Elected President

Lyndon B. Johnson
Democratic

Elections in Iowa

Iowa was won by incumbent President Lyndon B. Johnson (D–Texas), with 61.88% of the popular vote, against Senator Barry Goldwater (R–Arizona), with 37.92% of the popular vote.[3][4] As of the 2016 presidential election, this is the last election in which Pottawattamie County, Plymouth County, Mahaska County, Mills County, Harrison County, Grundy County, Shelby County, Montgomery County, Fremont County, Ida County, and Osceola County voted for the Democratic candidate.

References
  1. "United States Presidential election of 1964 - Encyclopædia Britannica". Retrieved May 30, 2017.
  2. "1964 Election for the Forty-Fifth Term (1965-69)". Retrieved May 30, 2017.
  3. "1964 Presidential General Election Results - Iowa". Retrieved May 30, 2017.
  4. "The American Presidency Project - Election of 1964". Retrieved May 30, 2017.


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