1920 Iowa gubernatorial election

The 1920 Iowa gubernatorial election was held on November 2, 1920. Republican nominee Nathan E. Kendall defeated Democratic nominee Clyde L. Herring with 58.66% of the vote.

1920 Iowa gubernatorial election
November 2, 1920
 
Nominee Nathan E. Kendall Clyde L. Herring
Party Republican Democratic
Popular vote 513,118 338,108
Percentage 58.66% 38.65%
Governor before election

William L. Harding
Republican

 Elected Governor

Nathan E. Kendall
Republican

Elections in Iowa

General election

Candidates

Major party candidates

  • Nathan E. Kendall, Republican
  • Clyde L. Herring, Democratic

Other candidates

  • George J. Peck, Socialist
  • Mathis Faber, Farmer–Labor
  • J. Jay Hisel, Socialist Labor

Results
1920 Iowa gubernatorial election[1]
Party Candidate Votes % ±
Republican Nathan E. Kendall 513,118 58.66%
Democratic Clyde L. Herring 338,108 38.65%
Socialist George J. Peck 13,671 1.56%
Farmer–Labor Mathis Faber 9,153 1.05%
Socialist Labor J. Jay Hisel 760 0.09%
Majority 175,010
Turnout
Republican hold Swing
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References
  1. "Guide to U.S. Elections". Books.google.com. Retrieved June 30, 2020.
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