1856 United States presidential election in Iowa
The 1856 United States presidential election in Iowa took place on November 4, 1856, as part of the 1856 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.
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Elections in Iowa | ||||||||||
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Iowa voted for the Republican candidate, John C. Frémont, over Democratic candidate, James Buchanan and American Party candidate Millard Fillmore. Frémont won Iowa by a margin of 8.13%.
Results
1856 United States presidential election in Iowa[1][2] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | John C. Frémont of California | William L. Dayton of New Jersey | 45,073 | 48.83% | 4 | 100.00% | ||
Democratic | James Buchanan of Pennsylvania | John C. Breckinridge of Kentucky | 37,568 | 40.70% | 0 | 0.00% | ||
Know Nothing | Millard Fillmore of New York | Andrew Jackson Donelson of Tennessee | 9,669 | 10.47% | 0 | 0.00% | ||
Total | 92,310 | 100.00% | 4 | 100.00% |
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gollark: <@293066066605768714> The netsplit was due to a failure of my internet connection briefly.
References
- "1856 Presidential General Election Results - Iowa". U.S. Election Atlas. Retrieved 3 December 2017.
- "1856 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 3 December 2017.
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