1928 United States presidential election in Nebraska
The 1928 United States presidential election in Nebraska was held on November 6, 1928. Nebraska voters chose eighteen electors to the Electoral College, who voted for president and vice president.
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The Republican candidate Herbert Hoover won the state by 147,786 votes or close to 27.01 percentage points against Al Smith.[1]
Results
1928 United States presidential election in Nebraska | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Herbert Hoover of California | Charles Curtis of Kansas | 345,745 | 63.19% | 8 | 100% | ||
Democratic | Al Smith of New York | Joseph Taylor Robinson of Arkansas | 197,959 | 36.18% | 0 | 0.00% | ||
Socialist | Norman Thomas of New York | James Hudson Maurer of Pennsylvania | 3,434 | 0.63% | 0 | 0.00% | ||
Various | Write-ins | Various | 6 | 0.00% | 0 | 0 | ||
Total | 547,144 | 100% | 8 | 100% |
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References
- "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved 2020-03-04.
Elections in Nebraska |
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