1956 Iowa gubernatorial election

The 1956 Iowa gubernatorial election was held on November 6, 1956. Democratic nominee Herschel C. Loveless defeated incumbent Republican Leo Hoegh with 51.22% of the vote.

1956 Iowa gubernatorial election
November 6, 1956
 
Nominee Herschel C. Loveless Leo Hoegh
Party Democratic Republican
Popular vote 616,852 587,383
Percentage 51.22% 48.78%
County results
Loveless:      50–60%      60–70%
Hoegh:      50-60%      60-70%
Governor before election

Leo Hoegh
Republican

 Elected Governor

Herschel C. Loveless
Democratic

Elections in Iowa

Primary elections

Primary elections were held on June 4, 1956.[1]

Democratic primary

Candidates

Results
Democratic primary results[1]
Party Candidate Votes %
Democratic Herschel C. Loveless 77,206 70.0
Democratic Lawrence E. Plummer 33,103 30.0
Total votes 110,309 100.00

Republican primary

Candidates

Results
Republican primary results[1]
Party Candidate Votes %
Republican Leo Hoegh 188,290 100.00
Total votes 188,290 100.00

General election

Candidates
  • Herschel C. Loveless, Democratic
  • Leo Hoegh, Republican

Results
1956 Iowa gubernatorial election[2]
Party Candidate Votes % ±
Democratic Herschel C. Loveless 616,852 51.22%
Republican Leo Hoegh 587,383 48.78%
Majority 29,469
Turnout 1,204,235
Democratic gain from Republican Swing
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References
  1. "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1956. Retrieved March 28, 2020.
  2. "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1956. Retrieved March 28, 2020.
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