1956 Iowa gubernatorial election

The 1956 Iowa gubernatorial election was held on November 6, 1956. Democratic nominee Herschel C. Loveless defeated incumbent Republican Leo Hoegh with 51.22% of the vote.

1956 Iowa gubernatorial election

November 6, 1956
 
Nominee Herschel C. Loveless Leo Hoegh
Party Democratic Republican
Popular vote 616,852 587,383
Percentage 51.22% 48.78%

County results
Loveless:      50–60%      60–70%
Hoegh:      50-60%      60-70%

Governor before election

Leo Hoegh
Republican

Elected Governor

Herschel C. Loveless
Democratic

Primary elections

Primary elections were held on June 4, 1956.[1]

Democratic primary

Candidates

Results

Democratic primary results[1]
Party Candidate Votes %
Democratic Herschel C. Loveless 77,206 70.0
Democratic Lawrence E. Plummer 33,103 30.0
Total votes 110,309 100.00

Republican primary

Candidates

Results

Republican primary results[1]
Party Candidate Votes %
Republican Leo Hoegh 188,290 100.00
Total votes 188,290 100.00

General election

Candidates

  • Herschel C. Loveless, Democratic
  • Leo Hoegh, Republican

Results

1956 Iowa gubernatorial election[2]
Party Candidate Votes % ±
Democratic Herschel C. Loveless 616,852 51.22%
Republican Leo Hoegh 587,383 48.78%
Majority 29,469
Turnout 1,204,235
Democratic gain from Republican Swing
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References

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