1968 United States presidential election in Iowa

The 1968 United States presidential election in Iowa took place on November 5, 1968, as part of the 1968 United States presidential election. Iowa voters chose nine[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

1968 United States presidential election in Iowa

November 5, 1968[1]
 
Nominee Richard Nixon Hubert Humphrey George Wallace
Party Republican Democratic American Independent
Home state New York[lower-alpha 1] Minnesota Alabama
Running mate Spiro Agnew Edmund Muskie Curtis LeMay
Electoral vote 9 0 0
Popular vote 619,106 476,699 66,422
Percentage 53.0% 40.8% 5.69%

County Results

President before election

Lyndon B. Johnson
Democratic

Elected President

Richard Nixon
Republican

Iowa was won by the Republican candidate, former Vice President Richard Nixon, with 53.01% of the popular vote, against the Democratic candidate, former Senator and incumbent Vice President Hubert Humphrey, with 40.82% of the popular vote. American Independent Party candidate George Wallace performed decently, finishing with 5.69% of the popular vote.[3][4]

Results

1968 United States presidential election in Iowa
Party Candidate Votes %
Republican Richard Nixon 619,106 53.01%
Democratic Hubert Humphrey 476,699 40.82%
American Independent George Wallace 66,422 5.69%
Socialist Workers Fred Halstead 3,377 0.29%
Write-in 2,327 0.20%
Total votes 1,167,931 100%
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References

Notes

  1. Although he was born in California and he served as a U.S. Senator from California, in 1968 Richard Nixon’s official state of residence was New York, because he moved there to practice law after his defeat in the 1962 California gubernatorial election. During his first term as president, Nixon re-established his residency in California. Consequently, most reliable reference books list Nixon's home state as New York in the 1968 election and his home state as California in the 1972 (and 1960) election.


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