1900 United States presidential election in Iowa
The 1900 United States presidential election in Iowa took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Iowa voters chose thirteen electors to the Electoral College, which selected the president and vice president.
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Elections in Iowa | ||||||||||
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Iowa was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.
Results
1900 United States presidential election in Iowa[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | William McKinley | 307,808 | 58.04% | 13 | |
Democratic | William Jennings Bryan | 209,265 | 39.46% | 0 | |
Prohibition | John Woolley | 9,502 | 1.79% | 0 | |
Social Democratic | Eugene Debs | 2,742 | 0.52% | 0 | |
Populist | Wharton Barker | 613 | 0.12% | 0 | |
Socialist Labor | Joseph Maloney | 259 | 0.05% | 0 | |
United Christian | Jonah Leonard | 166 | 0.03% | 0 | |
Totals | 530,355 | 100.00% | 13 | ||
Voter turnout | — |
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References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Iowa
Notes
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