1944 Iowa gubernatorial election

The 1944 Iowa gubernatorial election was held on November 7, 1944. Republican nominee Robert D. Blue defeated Democratic nominee Richard F. Mitchell with 56.01% of the vote.

1944 Iowa gubernatorial election
November 7, 1944
 
Nominee Robert D. Blue Richard F. Mitchell
Party Republican Democratic
Popular vote 561,827 437,684
Percentage 56.01% 43.63%
Governor before election

Bourke B. Hickenlooper
Republican

 Elected Governor

Robert D. Blue
Republican

Elections in Iowa

Primary elections

Primary elections were held on June 5, 1944.[1]

Democratic primary

Candidates

Results
Democratic primary results[1]
Party Candidate Votes %
Democratic Richard F. Mitchell 38,086 100.00
Total votes 38,086 100.00

Republican primary

Candidates

Results
Republican primary results[1]
Party Candidate Votes %
Republican Robert D. Blue 102,246
Republican Henry W. Burma 63,011
Republican Milton W. Strickler 9,859
Total votes

General election

Candidates

Major party candidates

  • Robert D. Blue, Republican
  • Richard F. Mitchell, Democratic

Other candidates

  • Glen Williamson, Prohibition
  • Hugo Bockewitz, Socialist

Results
1944 Iowa gubernatorial election[2]
Party Candidate Votes % ±
Republican Robert D. Blue 561,827 56.01%
Democratic Richard F. Mitchell 437,684 43.63%
Prohibition Glen Williamson 2,815 0.28%
Socialist Hugo Bockewitz 832 0.08%
Majority 124,143
Turnout
Republican hold Swing
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References
  1. "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1944. Retrieved April 14, 2020.
  2. "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1944. Retrieved April 14, 2020.
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