1856 United States presidential election in Arkansas

The 1856 United States presidential election in Arkansas was held on November 4, 1856. Arkansas voters chose four electors to represent the state in the Electoral College, which chose the president and vice president.

November 4, 1856
 
Nominee James Buchanan Millard Fillmore
Party Democratic Know Nothing
Home state Pennsylvania New York
Running mate John C. Breckinridge Andrew J. Donelson
Electoral vote 4 0
Popular vote 21,910 10,732
Percentage 67.12% 32.88%
President before election

Franklin Pierce
Democratic

 Elected President

James Buchanan
Democratic

Elections in Arkansas
Main article: 1856 United States presidential election

Arkansas voted for the Democratic nominee James Buchanan, who received 67% of the vote.[1]

Republican Party nominee John C. Frémont was not on the ballot.

Results
United States presidential election in Arkansas, 1856
Party Candidate Votes %
Democratic James Buchanan 21,910 67.12%
Know Nothing Millard Fillmore 10,732 32.88%
Total votes 32,642 100%
gollark: False dichotomy.
gollark: Interesting.
gollark: The parallels to our current discussion are obvious.
gollark: Consider also the following scenario.
gollark: It's obviously named after the Ben who used to be at my school and now works at GSK.

References
  1. "1856 Presidential General Election Results - Arkansas". David Leip's U.S. Election Atlas. Retrieved 2017-06-05.


This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.