1832 United States presidential election in Alabama
The 1832 United States presidential election in Alabama took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
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Elections in Alabama | ||||||||
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Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Alabama by a margin of 99.94%.
Results
United States presidential election in Alabama, 1832[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 14,286 | 99.97% | 7 | |
National Republican | Henry Clay | 5 | 0.03% | 0 | |
Totals | 14,291 | 100.0% | 7 | ||
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References
- "1832 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved 10 April 2013.
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