1832 United States presidential election in Tennessee
The 1832 United States presidential election in Tennessee took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for President and Vice President.
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| Elections in Tennessee | ||||||||
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Tennessee voted for the Democratic Party candidate, state native Andrew Jackson, over the National Republican candidate, Henry Clay. Jackson won Tennessee by a large margin of 90.84%.
Results
| United States presidential election in Tennessee, 1832[1] | |||||
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| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic | Andrew Jackson | 28,078 | 95.42% | 15 | |
| National Republican | Henry Clay | 1,347 | 4.58% | 0 | |
| Totals | 26,731 | 100.0% | 15 | ||
gollark: The hint is a lie.
gollark: I think it's totally a valid interpretation. *mumble mumble death of the author or something*
gollark: What do you mean he has "no cows"?
gollark: Well, obviously he... needs help handling purple cows, this isn't very hard.
gollark: What are you even talking about ˙?!
References
- "1832 Presidential General Election Results - Tennessee". U.S. Election Atlas. Retrieved 12 April 2013.
State and district results of the 1832 United States presidential election | ||
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