1832 United States presidential election in Ohio

1832 United States presidential election in Ohio
	November 2 – December 5, 1832
	November 2 – December 5, 1832
President before election; Andrew Jackson; Democratic	Elected President ; Andrew Jackson; Democratic

The 1832 United States presidential election in Ohio took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 21 representatives, or electors to the Electoral College, who voted for President and Vice President.

Ohio voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay, and the Anti-Masonic Party candidate, William Wirt. Jackson won Ohio by a margin of 2.98%.

Results

1832 United States presidential election in Ohio[1]
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Andrew Jackson	81,246	51.33%	21
	National Republican	Henry Clay	76,539	48.35%	0
	Anti-Masonic	William Wirt	509	0.32%	0
Totals			158,294	100.0%	21

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