1832 United States presidential election in Ohio
The 1832 United States presidential election in Ohio took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose 21 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Ohio | ||||||||||||||||||||
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Ohio voted for the Democratic Party candidate, Andrew Jackson, over the National Republican candidate, Henry Clay, and the Anti-Masonic Party candidate, William Wirt. Jackson won Ohio by a margin of 2.98%.
Results
1832 United States presidential election in Ohio[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 81,246 | 51.33% | 21 | |
National Republican | Henry Clay | 76,539 | 48.35% | 0 | |
Anti-Masonic | William Wirt | 509 | 0.32% | 0 | |
Totals | 158,294 | 100.0% | 21 | ||
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References
- "1832 Presidential General Election Results - Ohio". U.S. Election Atlas. Retrieved 12 April 2013.
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