1900 United States presidential election in Nebraska
The 1900 United States presidential election in Nebraska took place on November 6, 1900. All contemporary 45 states were part of the 1900 United States presidential election. Voters chose eight electors to the Electoral College, which selected the president and vice president.
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| Elections in Nebraska |
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Nebraska was won by the Republican nominees, incumbent President William McKinley of Ohio and his running mate Theodore Roosevelt of New York.
Democratic Party candidate William Jennings Bryan lost his home state to McKinley by a margin of 3.24%. Bryan had previously defeated McKinley in the state four years earlier and would later win it again against William Howard Taft in 1908.
Results
| 1900 United States presidential election in Nebraska[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | William McKinley | 121,835 | 50.46% | 8 | |
| Democratic | William Jennings Bryan | 114,013 | 47.22% | 0 | |
| Prohibition | John Woolley | 3,655 | 1.51% | 0 | |
| Populist | Wharton Barker | 1,104 | 0.46% | 0 | |
| Social Democratic | Eugene Debs | 823 | 0.34% | 0 | |
| Totals | 241,430 | 100.00% | 8 | ||
| Voter turnout | — | ||||
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References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Nebraska
Notes
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