1892 United States presidential election in Nebraska
The 1892 United States presidential election in Nebraska took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Voters chose eight electors to the Electoral College, which selected the president and vice president.
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Elections in Nebraska |
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Nebraska was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York. Harrison and Reid narrowly defeated the Populist nominees, James B. Weaver of Iowa and his running mate James G. Field of Virginia, with national winner and Democratic nominees Grover Cleveland and Adlai Stevenson I a distant third and carrying only Thomas County by plurality.[1]
Alongside 1908, this is one of only two elections where Nebraska did not vote the same as neighboring Kansas,[lower-alpha 1] and Weaver’s is the best-ever third party performance in Nebraska presidential election history.
Results
1892 United States presidential election in Nebraska[2] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | Benjamin Harrison (incumbent) | 87,213 | 43.56% | 8 | |
People's | James Weaver | 83,134 | 41.53% | 0 | |
Democratic | Grover Cleveland | 24,943 | 12.46% | 0 | |
Prohibition | John Bidwell | 4,902 | 2.45% | 0 | |
Totals | 200,192 | 100.00% | 8 | ||
Voter turnout | — |
Notes
- In 2008, although John McCain carried both states, Democrat Barack Obama won Nebraska's second congressional district and won one electoral vote therefrom, whilst McCain won all Kansas votes and the remaining four Nebraska votes.
References
- Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 250-251 ISBN 0786422173
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Nebraska