1892 United States presidential election in South Dakota
The 1892 United States presidential election in South Dakota took place on November 8, 1892. All contemporary 44 states were part of the 1892 United States presidential election. Voters chose four electors to the Electoral College, which selected the president and vice president.
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| Elections in South Dakota |
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South Dakota participated in its first ever presidential election, having been admitted as the 40th state on November 2, 1889. The state was won by the Republican nominees, incumbent President Benjamin Harrison of Indiana and his running mate Whitelaw Reid of New York. Harrison and Reid defeated the Populist nominees, James B. Weaver of Iowa and his running mate James G. Field of Virginia and the Democratic candidates, former (and future) President Grover Cleveland of New York and his running mate Adlai Stevenson of Illinois.
Harrison won the state by a margin of 11.84 percentage points, become both the first Republican presidential candidate and first ever presidential candidate to win the state.
Results
| 1892 United States presidential election in South Dakota[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | Benjamin Harrison (incumbent) | 34,888 | 49.48% | 4 | |
| People's | James Weaver | 26,544 | 37.64% | 0 | |
| Democratic | Grover Cleveland | 9,081 | 12.88% | 0 | |
| Totals | 70,513 | 100.00% | 4 | ||
| Voter turnout | — | ||||
References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – South Dakota
