1869 Vermont gubernatorial election
The 1869 Vermont gubernatorial election took place on September 7, 1869. Incumbent Republican John B. Page, per the "Mountain Rule",[1] did not run for re-election to another term as Governor of Vermont. Republican candidate Peter T. Washburn defeated Democratic candidate Homer W. Heaton to succeed him. The 1869 election was the final time the Governor of Vermont was elected for a one-year term, changing to a two-year term at the 1870 election.
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Results
Party | Candidate | Votes | % | ± | |
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Republican | Peter T. Washburn | 31,834 | 73.5 | 0.0 | |
Democratic | Homer W. Heaton | 11,455 | 26.4 | 0.0 | |
N/A | Other | 26 | 0.1 | 0.0 | |
Total votes | '43,315' | '100' | – |
References
- Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 4 October 2015.
- "General Election Results - Governor - 1789-2012" (PDF). Office of the Vermont Secretary of State. Retrieved 4 October 2015.
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