1866 Vermont gubernatorial election

The 1867 Vermont gubernatorial election took place on September 4, 1866.[1] In keeping with the "Mountain Rule",[2] Incumbent Republican Paul Dillingham was a candidate for a second one-year term as governor of Vermont.[3] With the election taking place soon after the American Civil War, Dillingham ran as a pro-Union Republican.[4] The Democratic nomination was won by Charles N. Davenport of Wilmington, an attorney and founder of the Brattleboro Reformer newspaper, who was also the Democratic nominee in 1865.[5][6] In the general election, Dillingham was easily elected to a second one-year term as governor.[7]

1866 Vermont gubernatorial election
September 4, 1866 (1866-09-04)
 
Candidate Paul Dillingham Charles N. Davenport
Party Republican Democratic
Popular vote 34,117 11,292
Percentage 75.1 24.9
Governor before election

Paul Dillingham
Republican

 Elected Governor

Paul Dillingham
Republican

Elections in Vermont

Results
Vermont gubernatorial election, 1866
Party Candidate Votes % ±
Republican Paul Dillingham 34,117 75.1
Democratic Charles N. Davenport 11,292 24.9
N/A Scattering 3 .00006
Total votes '45,112' '100'
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References
  1. "Latest News: Vermont Elections". Rutland Herald. Rutland, VT. September 5, 1866. p. 1 – via Newspapers.com.
  2. Hand, Samuel B. "Mountain Rule Revisited" (PDF). Vermont Historical Society. Retrieved 5 January 2016.
  3. "Republican State Ticket". Burlington Free Press. Burlington, VT. June 22, 1866. p. 2 – via Newspapers.com.
  4. "Union State Nominations". The Vermont Phoenix. Brattleboro, VT. August 31, 1866. p. 2 – via Newspapers.com.
  5. "Democratic State Ticket". North Star. Danville, VT. September 1, 1866. p. 3 – via Newspapers.com.
  6. Walbridge, J. H. (1900). Wilmington, Vermont. Wilmington, VT: Deerfield Valley Times Press. p. 21 – via Google Books.
  7. "1866 Governor General Election". Vermont Elections Database. Montpelier, VT: Vermont Secretary of State. Retrieved June 10, 2020.
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