1844 United States presidential election in Kentucky

The 1844 United States presidential election in Kentucky took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for President and Vice President.

Main article: 1844 United States presidential election
United States presidential election in Kentucky, 1844
November 1 - December 4, 1840
 
Nominee Henry Clay James K. Polk
Party Whig Democratic
Home state Kentucky Tennessee
Running mate Theodore Frelinghuysen George M. Dallas
Electoral vote 12 0
Popular vote 61,249 51,988
Percentage 54.09% 45.91%
President before election

John Tyler
Independent

 Elected President

James K. Polk
Democratic

Elections in Kentucky
Government

Kentucky voted for the Whig candidate, Henry Clay, over Democratic candidate James K. Polk. Clay won his home state by a margin of 8.18%.

With 54.09% of the popular vote, Clay's home state would be his third strongest victory after Rhode Island and Vermont.[1]

Results
United States presidential election in Kentucky, 1844[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Whig Henry Clay of Kentucky Theodore Frelinghuysen of New York 61,249 54.09% 12 100.00%
Democratic James K. Polk of Tennessee George M. Dallas of Pennsylvania 51,988 45.91% 0 0.00%
Total 113,237 100.00% 12 100.00%
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References
  1. "1844 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. "1844 Presidential General Election Results - Kentucky". U.S. Election Atlas. Retrieved 23 December 2013.


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