1844 United States presidential election in Louisiana
The 1844 United States presidential election in Louisiana took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose six representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Louisiana |
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Presidential Elections
U.S. Senate
U.S. House
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State elections by year
Gubernatorial
Lieutenant gubernatorial Attorney General |
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Louisiana voted for the Democratic candidate, James K. Polk, over Whig candidate Henry Clay. Polk won Louisiana by a margin of 2.6%.
Results
United States presidential election in Louisiana, 1844[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | James K. Polk of Tennessee | George M. Dallas of Pennsylvania | 13,782 | 51.30% | 6 | 100.00% | ||
Whig | Henry Clay of Kentucky | Theodore Frelinghuysen of New York | 13,083 | 48.70% | 0 | 0.00% | ||
Total | 26,865 | 100.00% | 6 | 100.00% |
gollark: Honestly I mostly use the internet nowadays, so more likely osmarks.
gollark: Or osmarks or gollark.
gollark: Oliver [REDACTED].
gollark: I was born there and lived there for a bit, although I live in England now.
gollark: Technically speaking, I'm sort of Scottish.
References
- "1844 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved 23 December 2013.
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