1828 United States presidential election in Indiana
The 1828 United States presidential election in Indiana took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Indiana | ||||||
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Indiana voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Indiana by a margin of 13.24%.
Results
1828 United States presidential election in Indiana[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 22,257 | 56.62% | 5 | |
National Republican | John Quincy Adams | 17,052 | 43.38% | 0 | |
Totals | 39,309 | 100.0% | 5 | ||
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gollark: Skirts are entirely reasonable, if bad, clothing.
gollark: Well, just die once, and do it 26 more times?
gollark: I don't see why you don't just issue yourself infinitely many citizenships.
gollark: Maybe the contingency systems were a bit useless.
References
- "1828 Presidential General Election Results - Indiana". U.S. Election Atlas. Retrieved 28 February 2013.
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