1828 United States presidential election in Alabama
The 1828 United States presidential election in Alabama took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Alabama | ||||||||
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Alabama voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Alabama by a margin of 79.80%.
Results
United States presidential election in Alabama, 1828[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 16,736 | 89.89% | 5 | |
National Republican | John Quincy Adams | 1,878 | 10.09% | 0 | |
N/A | Other | 4 | 0.02% | 0 | |
Totals | 18,618 | 100.0% | 5 | ||
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References
- "1828 Presidential General Election Results - Alabama". U.S. Election Atlas. Retrieved 28 February 2013.
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