1904 United States presidential election in Nebraska
The 1904 United States presidential election in Nebraska took place on November 8, 1904. All contemporary 45 states were part of the 1904 United States presidential election. Voters chose eight electors to the Electoral College, which selected the president and vice president.
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| Elections in Nebraska |
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Nebraska was won by the Republican nominees, incumbent President Theodore Roosevelt of New York and his running mate Charles W. Fairbanks of Indiana. Roosevelt won the state by a margin of 37.94 percentage points.
Results
| 1904 United States presidential election in Nebraska[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Republican | Theodore Roosevelt | 138,558 | 61.38% | 8 | |
| Democratic | Alton B. Parker | 52,921 | 23.44% | 0 | |
| Populist | Thomas E. Watson | 20,518 | 9.09% | 0 | |
| Social Democratic | Eugene Debs | 7,412 | 3.28% | 0 | |
| Prohibition | Silas C. Swallow | 6,323 | 2.80% | 0 | |
| Totals | 225,732 | 100.00% | 8 | ||
| Voter turnout | — | ||||
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References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Nebraska
Notes
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