1976 United States presidential election in Nebraska

The 1976 United States presidential election in Nebraska took place on November 2, 1976, as part of the 1976 United States presidential election. Voters chose five representatives, or electors, to the Electoral College, who voted for president and vice president.

1976 United States presidential election in Nebraska

November 2, 1976
 
Nominee Gerald Ford Jimmy Carter
Party Republican Democratic
Home state Michigan Georgia
Running mate Bob Dole Walter Mondale
Electoral vote 5 0
Popular vote 359,705 233,692
Percentage 59.2% 38.5%

County Results

President before election

Gerald Ford
Republican

Elected President

Jimmy Carter
Democratic

Nebraska was won by incumbent President Gerald Ford (RMichigan), with 59.19% of the popular vote, against Jimmy Carter (DGeorgia), with 38.46% of the popular vote. None of the third-party candidates amounted to a significant portion of the vote, but Eugene McCarthy (IMinnesota) won 1.55% of Nebraska's popular vote and came third overall in the nation. Despite losing in Nebraska, Carter went on to win the national election and became the 39th president of the United States.[1] As of the 2016 presidential election, this is the last election in which Butler County, Sherman County, and Greeley County voted for the Democratic candidate.

With 59.19% of the popular vote, Nebraska, where Ford was born as Leslie Lynch King in 1913, proved to be Ford's fourth strongest state in the 1976 election after Utah, Idaho and Wyoming.[2]

Results

1976 United States presidential election in Nebraska
Party Candidate Votes %
Republican Gerald Ford (inc.) 359,705 59.19%
Democratic Jimmy Carter 233,692 38.46%
Independent Eugene McCarthy 9,409 1.55%
American Independent Lester Maddox 3,380 0.56%
Libertarian Roger MacBride 1,482 0.24%
Total votes 607,668 100%

References

  1. http://uselectionatlas.org/RESULTS/index.html
  2. "1976 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.


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