1948 United States presidential election in Nebraska
The 1948 United States presidential election in Nebraska took place on November 2, 1948, as part of the 1948 United States presidential election. Voters chose six[2] representatives, or electors, to the Electoral College, who voted for president and vice president.
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All 6 Nebraska votes to the Electoral College | ||||||||||||||||||||||||||
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County Results
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Elections in Nebraska |
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Nebraska was won by Governor Thomas Dewey (R–New York), running with Governor Earl Warren, with 54.15% of the popular vote, against incumbent President Harry S. Truman (D–Missouri), running with Senator Alben W. Barkley, with 45.85% of the popular vote.[3][4] As of the 2016 presidential election, this is the last occasion Wheeler County has voted for a Democratic presidential candidate.[5]
With 54.15% of the popular vote, Nebraska would prove to be Dewey's third strongest state in the nation after Vermont and Maine.[6]
Results
Party | Candidate | Votes | % | |
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Republican | Thomas Dewey | 264,774 | 54.15% | |
Democratic | Harry S. Truman (inc.) | 224,165 | 45.85% | |
Write-in | 1 | 0.00% | ||
Total votes | 488,940 | 100% |
References
- "United States Presidential election of 1948 - Encyclopædia Britannica". Retrieved December 20, 2017.
- "1948 Election for the Forty-First Term (1949-53)". Retrieved December 20, 2017.
- "1948 Presidential General Election Results – Nebraska". Retrieved December 20, 2017.
- "The American Presidency Project - Election of 1948". Retrieved December 20, 2017.
- Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016
- "1948 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.