1948 United States presidential election in Wisconsin

1948 United States presidential election in Wisconsin
	November 2, 1948
	November 2, 1948
Truman 40-50% 50-60% 60-70%	Dewey 40-50% 50-60% 60-70%
President before election; Harry S. Truman; Democratic	Elected President ; Harry S. Truman; Democratic

The 1948 United States presidential election in Wisconsin was held on November 2, 1948 as part of the 1948 United States presidential election. State voters chose twelve electors to the Electoral College, who voted for president and vice president.

Democratic Party candidate Harry S. Truman won Wisconsin with 51% of the popular vote, winning the state's twelve electoral votes.[1]

Results

1948 United States presidential election in Wisconsin
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Harry S. Truman	647,310	50.70%	12
	Republican	Thomas E. Dewey	590,959	46.28%	0
	Progressive	Henry A. Wallace	25,282	1.98%	0
	Socialist	Norman Thomas	12,547	0.98%	0
Totals			1,276,098	100.0%	12

gollark: And they probably want people to use OOP awfulness and "code standards".

gollark: And I'm expected to do *unit tests*.

gollark: And people will complain if a config tweak takes down everything for 20 minutes.

gollark: The industry is æ. They have "deadlines" and "requirements" and use bad languages I don't like.

gollark: Anyway, I haven't really decided much yet, but I *probably* don't really want to work in software as a job.

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