1896 United States presidential election in Wisconsin

The 1896 United States presidential election in Wisconsin was held on November 3, 1896 as part of the 1896 United States presidential election. State voters chose twelve electors to the Electoral College, who voted for president and vice president.

Main article: 1896 United States presidential election
1896 United States presidential election in Wisconsin
November 3, 1896
 
Nominee William McKinley William Jennings Bryan
Party Republican Democratic
Home state Ohio Nebraska
Running mate Garret Hobart Arthur Sewall
Electoral vote 12 0
Popular vote 268,135 165,523
Percentage 59.93% 37.0%
President before election

Grover Cleveland
Democratic

 Elected President

William McKinley
Republican

Elections in Wisconsin

Republican Party candidate William McKinley won Wisconsin with 60% of the popular vote, winning the state's twelve electoral votes.[1]

Results
1896 United States presidential election in Wisconsin
Party Candidate Votes Percentage Electoral votes
Republican William McKinley 268,135 59.93% 12
Democratic William Jennings Bryan 165,523 37.0% 0
Prohibition Joshua Levering 7,507 1.68% 0
National Democratic John M. Palmer 4,584 1.02% 0
Socialist Labor Charles H. Matchett 1,314 0.29% 0
National Prohibition Charles E. Bentley 346 0.08% 0
Totals 447,409 100.0% 12
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References
  1. "1896 Presidential General Election Results - Wisconsin". Retrieved August 18, 2016.
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