1896 United States presidential election in Maryland
The 1896 United States presidential election in Maryland took place on November 3, 1896. All contemporary 45 states were part of the 1896 United States presidential election. Maryland voters chose 8 electors to the Electoral College, which selected the president and vice president.
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Elections in Maryland | ||||||||
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Elections by year |
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Maryland was won by the Republican nominees, former Ohio Governor William McKinley and his running mate Garret Hobart of New Jersey.
This was the first time that a Republican won Maryland since 1864 and the Democrats would not win the state's popular vote until 1912.
Results
United States presidential election in Maryland, 1896[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | William McKinley | 136,959 | 54.73% | 8 | |
Democratic | William Jennings Bryan | 104,150 | 41.62% | 0 | |
Prohibition | Joshua Levering | 5,918 | 2.36% | 0 | |
National Democratic | John M. Palmer | 2,499 | 1.00% | 0 | |
Socialist Labor | Charles Matchett | 587 | 0.23% | 0 | |
National Prohibition | Charles Bentley | 136 | 0.05% | 0 | |
Totals | 250,249 | 100.00% | 8 | ||
Voter turnout | — |
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References
- Dave Leip's U.S. Election Atlas; Presidential General Election Results – Maryland
Notes
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