1836 United States presidential election in Maryland
The 1836 United States presidential election in Maryland took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 10 representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Maryland | ||||||||
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Elections by year |
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Maryland voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Maryland by a margin of 7.46%.
Results
United States presidential election in Maryland, 1836[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Whig | William Henry Harrison | 25,852 | 53.73% | 10 | |
Democratic | Martin Van Buren | 22,267 | 46.27% | 0 | |
Totals | 48,119 | 100.0% | 10 | ||
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References
- "1836 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 4 August 2012.
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