1988 United States presidential election in Louisiana

The 1988 United States presidential election in Louisiana took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for president and vice president.

Main article: 1988 United States presidential election

1988 United States presidential election in Louisiana

November 8, 1988

Nominee George H.W. Bush Michael Dukakis Party Republican Democratic Home state Texas Massachusetts Running mate Dan Quayle Lloyd Bentsen Electoral vote 10 0 Popular vote 883,702 717,460 Percentage 54.27% 44.06%

Parish Results Bush   40–50%   50–60%   60–70%   70–80% Dukakis   40–50%   50–60%   60–70%

President before election Ronald Reagan Republican Elected President George H.W. Bush Republican

Louisiana strongly voted for the Republican nominee, Vice President George H. W. Bush, over the Democratic nominee, Massachusetts governor Michael Dukakis. The margin was 10%, which was nonetheless the best Southern state showing for Dukakis. As of the 2016 presidential election, this is the last election in which Tensas Parish voted for a Republican presidential candidate.[1]

Results

United States presidential election in Louisiana, 1988[2]
Party		Candidate	Votes	Percentage	Electoral votes
	Republican	George H. W. Bush	883,702	54.27%	10
	Democratic	Michael Dukakis	717,460	44.06%	0
	America First	David Duke	18,612	1.14%	0
	Libertarian	Ron Paul	4,115	0.25%	0
	New Alliance	Lenora Fulani	2,355	0.14%	0
	Democrats for Economic Recovery	Lyndon LaRouche	1,958	0.12%	0
Invalid or blank votes					—
Totals			1,628,202	100.00%	10
Voter turnout					—

References

1. Sullivan, Robert David; ‘How the Red and Blue Map Evolved Over the Past Century’; America Magazine in The National Catholic Review; June 29, 2016
2. "1988 Presidential General Election Results – Louisiana". Dave Leip’s U.S. Election Atlas. Retrieved 2008-08-25.