1836 United States presidential election in Louisiana
The 1836 United States presidential election in Louisiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
|
Elections in Louisiana |
---|
Presidential Elections
U.S. Senate
U.S. House
|
State elections by year
Gubernatorial
Lieutenant gubernatorial Attorney General |
|
Louisiana voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Louisiana by a margin of 3.48%.
Results
United States presidential election in Louisiana, 1836[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 3,842 | 51.74% | 5 | |
Whig | Hugh White | 3,583 | 48.26% | 0 | |
Totals | 7,425 | 100.0% | 5 | ||
gollark: Can you think of additional stats it should track at the side?
gollark: The editing UI *does* look rather nice though.
gollark: I mean, there are comments, but not very good ones, and it's a bit of a mess.
gollark: I wonder if I should be worried about minoteaur now incorporating about 298 lines of frontend JS with ~0 comments.
gollark: Obviously.
References
- "1836 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved 4 August 2012.
This article is issued from Wikipedia. The text is licensed under Creative Commons - Attribution - Sharealike. Additional terms may apply for the media files.