1836 United States presidential election in Louisiana
The 1836 United States presidential election in Louisiana took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
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Elections in Louisiana |
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Presidential Elections
U.S. Senate
U.S. House
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State elections by year
Gubernatorial
Lieutenant gubernatorial Attorney General |
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Louisiana voted for the Democratic candidate, Martin Van Buren, over Whig candidate Hugh White. Van Buren won Louisiana by a margin of 3.48%.
Results
United States presidential election in Louisiana, 1836[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Martin Van Buren | 3,842 | 51.74% | 5 | |
Whig | Hugh White | 3,583 | 48.26% | 0 | |
Totals | 7,425 | 100.0% | 5 | ||
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References
- "1836 Presidential General Election Results - Louisiana". U.S. Election Atlas. Retrieved 4 August 2012.
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