1864 United States presidential election in Michigan
The 1864 United States presidential election in Michigan took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose eight[1] representatives, or electors, to the Electoral College, who voted for president and vice president.[2]
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![]() Results by county
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Elections in Michigan | ||||||||||
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Michigan was won by incumbent president Abraham Lincoln over Democratic challenger George B. McClellan by a margin of 7.2%.[2]
As of the 2016 presidential election, this is the last time Ottawa County voted for a Democratic Presidential candidate.[3]
Results
Party | Candidate | Votes | % | |
---|---|---|---|---|
National Union | Abraham Lincoln | 79,149 | 53.60% | |
Democratic | George B. McClellan | 68,513 | 46.40% | |
Total votes | 147,662 | 100% |
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References
- "1864 Election for the Twentieth Term (1865-1869)". Retrieved 2018-11-28.
- "1864 Presidential General Election Results - Michigan".
- Menendez, Albert J.; The Geography of Presidential Elections in the United States, 1868-2004, pp. 222-227 ISBN 0786422173
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